Jake T. Austin Height is 5′ 8″ [5 feet 8 Inches]
i.e. 173 cm and 1.73 m
| Jake T. AustinPersonal Information |
| Name | Jake T. Austin |
| Nickname | N/A |
| Profession | Actor |
| Age | 26 years [as of December 2020] |
| Birthplace | New York City, United States |
| Date Of Birth | December 3, 1994 |
| Weight | 65 Kg, 143 Lbs |
| Nationality | American |
| DebutFilm | The Ant Bully (2006) |
| Father’s Name | Joey Szymanski |
| Mother’s Name | Giny Szymanski |
| Brother(s) | N/A |
| Sister(s) | Ava Szymanski |
| Birth Sign | Sagittarius |
| Spouse | N/A |
| Girlfriend(s) | Danielle Ceasar |
| Children | N/A |
| Net Worth | $5 Million |
| Awards Won | 1 |
| School | N/A |
| College | N/A |
See Also: Colin Ford Height, Weight, Age, Family, Bio, Wiki, Net Worth And More
SHORT BIO:
Jake Austin Szymanski was born on December 3, 1994 in New York, United States. He is known for films like Tom Sawyer & Huckleberry Finn (2014), Justice League vs. Teen Titans (2016), Teen Titans: The Judas Contract (2017) and more. He has also appeared in a several Television shows.
SOCIAL MEDIA:
@YouTube
[Connect with Jake T. Austin on his Social Media for latest updates]
AWARDS WON:
- Hollywood Teen TV Awards for work Wizards of Waverly Place in 2012
Image: Via Wikimedia