March 27

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Jake T. Austin Height, Weight, Age, Family, Bio, Wiki, Net Worth And More

Jake T. Austin Height is 5′ 8″ [5 feet 8 Inches]
i.e. 173 cm and 1.73 m

Jake T. AustinPersonal Information
NameJake T. Austin
NicknameN/A
ProfessionActor
Age26 years [as of December 2020]
BirthplaceNew York City, United States
Date Of BirthDecember 3, 1994
Weight65 Kg, 143 Lbs
NationalityAmerican
DebutFilmThe Ant Bully (2006)
Father’s NameJoey Szymanski
Mother’s NameGiny Szymanski
Brother(s)N/A
Sister(s)Ava Szymanski
Birth SignSagittarius
SpouseN/A
Girlfriend(s)Danielle Ceasar
ChildrenN/A
Net Worth$5 Million
Awards Won1
SchoolN/A
CollegeN/A

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SHORT BIO:

Jake Austin Szymanski was born on December 3, 1994 in New York, United States. He is known for films like Tom Sawyer & Huckleberry Finn (2014), Justice League vs. Teen Titans (2016), Teen Titans: The Judas Contract (2017) and more. He has also appeared in a several Television shows.

SOCIAL MEDIA:

@Instagram

@Twitter

@YouTube

@Facebook

[Connect with Jake T. Austin on his Social Media for latest updates]

AWARDS WON:

  • Hollywood Teen TV Awards for work Wizards of Waverly Place in 2012

Image: Via Wikimedia

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